20x^2=x+1

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Solution for 20x^2=x+1 equation:


Simplifying
20x2 = x + 1

Reorder the terms:
20x2 = 1 + x

Solving
20x2 = 1 + x

Solving for variable 'x'.

Reorder the terms:
-1 + -1x + 20x2 = 1 + x + -1 + -1x

Reorder the terms:
-1 + -1x + 20x2 = 1 + -1 + x + -1x

Combine like terms: 1 + -1 = 0
-1 + -1x + 20x2 = 0 + x + -1x
-1 + -1x + 20x2 = x + -1x

Combine like terms: x + -1x = 0
-1 + -1x + 20x2 = 0

Factor a trinomial.
(-1 + -5x)(1 + -4x) = 0

Subproblem 1

Set the factor '(-1 + -5x)' equal to zero and attempt to solve: Simplifying -1 + -5x = 0 Solving -1 + -5x = 0 Move all terms containing x to the left, all other terms to the right. Add '1' to each side of the equation. -1 + 1 + -5x = 0 + 1 Combine like terms: -1 + 1 = 0 0 + -5x = 0 + 1 -5x = 0 + 1 Combine like terms: 0 + 1 = 1 -5x = 1 Divide each side by '-5'. x = -0.2 Simplifying x = -0.2

Subproblem 2

Set the factor '(1 + -4x)' equal to zero and attempt to solve: Simplifying 1 + -4x = 0 Solving 1 + -4x = 0 Move all terms containing x to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + -4x = 0 + -1 Combine like terms: 1 + -1 = 0 0 + -4x = 0 + -1 -4x = 0 + -1 Combine like terms: 0 + -1 = -1 -4x = -1 Divide each side by '-4'. x = 0.25 Simplifying x = 0.25

Solution

x = {-0.2, 0.25}

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